Aarya - Maths tutor - Chennai
1st lesson free
Aarya - Maths tutor - Chennai

Aarya's profile and their contact details have been verified by our experts

Aarya

  • Price $5
  • Answer 3h
  • Students

    Number of students Aarya has accompanied since arriving at Superprof

    1

    Number of students Aarya has accompanied since arriving at Superprof

Aarya - Maths tutor - Chennai
  • 5 (3 reviews)

$5/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic
  • Geometry

2nd year engineering student pursuing ECE from Vellore Institute of Technology, proficient in mental maths and problem solving

  • Maths
  • Algebra
  • Trigonometry
  • Arithmetic
  • Geometry

Lesson location

Recommended

Aarya is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.

About Aarya

As a kid, I found math to be just another subject filled with boring books and endless memorization. It never felt exciting—until I started turning it into games. Instead of just solving problems, I played with numbers, turning equations into puzzles and challenges. Now, as an engineering student, I use the same approach to teach my roommates, friends, and even my younger cousins. Watching them go from fearing math to enjoying it, sharpening their skills along the way, has been incredibly rewarding. Math is no longer a ghost to them—it’s just another puzzle waiting to be solved.

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About the lesson

  • Primary School
  • High School
  • Year 10
  • +2
  • levels :

    Primary School

    High School

    Year 10

    Year 11-12

    Early childhood education

  • English

All languages in which the lesson is available :

English

Aren't you bored of studying trigonometry in the same old way what if you are an explorer searching for an ancient relic hidden deep in a lost temple. The only way to navigate through obstacles and find the relic is by using trigonometry!

Challenge 1: The Rope Bridge (Right Triangle Basics)

You reach a broken rope bridge across a canyon. A tree stands 20m away, and a vine is tied 30m up in the tree. You need to calculate the angle at which you must swing to reach the other side safely.

Problem:
Find θ, where:

Opposite = 30m (height of the tree)

Adjacent = 20m (distance to the tree)

tan(θ) = opposite/adjacent


Solution:
θ = tan⁻¹(30/20) = tan⁻¹(1.5) ≈ 56.3°

Simple enough isn't it well it can be even more fun and insightful with me not only for trigonometry but for anything that you can think of at this point in mathematics you name it and you learn it easily with me.

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Rates

Price

  • $5

Pack prices

  • 5h: $25
  • 10h: $43

online

  • $5/h

free lessons

The first lesson with Aarya will allow you to get to know each other and discuss your needs for future lessons.

  • 1hr

Details

Will include personally dedicated 1 hour to the student, the fees includes extra doubt sessions and tests and quizzes as well

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