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Arowojolu
- Price $4
- Answer 1h
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- Maths
- Algebra
- Trigonometry
- Algorithms
Teaches for all level. And breaking all workings into simplex form. It will be very fun.
- Maths
- Algebra
- Trigonometry
- Algorithms
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About Arowojolu
Am a very cool and calm teacher who loves teaching and eradicate students knowledge. I love challenging my student when it comes to Mathematics.
Because mathematics is like a puzzle game before you play,you have to think very well. At the endyouwill see that mathematics help you to think fast.
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About the lesson
- Primary School
- High School
- Year 10
- +7
levels :
Primary School
High School
Year 10
Year 11-12
Year 12
Adult
Undergraduate
Diploma/Certificate
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- English
All languages in which the lesson is available :
English
Find a number such that when it is successively added to 5 and subtracted from 15, the product of the two results is 96.
SOLUTION
Let the number be any variable e.g x or y
Let say we pick "x" as the number.
Then 5 is added i.e (x+5)
Also x is subtracted from 15 i.e (15-x)
Then the product of the two results is 96.
I.e (x+5)(15-x)=96
By expanding the bracket
X(15-x)+5(15-x)=96
15x-x²+75-5x-96=0
By rearranging
x²-10x+21=0
By factorization method
(x-3)(x-7)=0
Therefore x=3 or x= 7
Hence the number is 3 or 7.
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Rates
Price
- $4
Pack prices
- 5h: $20
- 10h: $40
online
- $4/h
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