Kayode - Maths tutor - Port Harcourt
1st lesson free
Kayode - Maths tutor - Port Harcourt

Kayode's profile and their contact details have been verified by our experts

Kayode

  • Price $5
  • Answer 24h
  • Students

    Number of students Kayode has accompanied since arriving at Superprof

    1

    Number of students Kayode has accompanied since arriving at Superprof

Kayode - Maths tutor - Port Harcourt
  • 5 (2 reviews)

$5/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

A dynamic and proficient Math tutor, incorporating sound knowledge of Engineering and Science to solving your mathematical problems. I teach the "understanding" of Math to aid your strength in not j

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

Lesson location

Recommended

Kayode is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.

About Kayode

I am a Civil Engineer but I've been passionate about teaching. I presently take home lessons and online tutorials in some other platforms. I engage the teaching of basic principle of mathematics and engineering to expose students to the concept behind each Mathematical problem and hence stir up your interest in not just the questions but the topic as a whole. Once you get the understanding of Mathematics, you can easily solve any question even beyond the scope of the particular question.

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About the lesson

  • Primary School
  • High School
  • Year 10
  • +8
  • levels :

    Primary School

    High School

    Year 10

    Year 11-12

    Year 12

    Adult

    Undergraduate

    Diploma/Certificate

    Postgraduate

    PhD

    Early childhood education

  • English

All languages in which the lesson is available :

English

Find the largest of three consecutive odd numbers whose sum is 57. Solution: Let the largest be x Consecutive odd numbers increase/decrease by difference of 2. This implies, other two numbers are (x-2) and (x-4) So, the sum; x + (x-2) + (x-4) = 57 Hence, solving, we have; 3x - 6= 57 Add 6 to both sides, 3x = 63 Dividing both sides by 3 X = 21. This implies that, the largest number is 21. Other two numbers are; X-2 => 21-2 = 19 X-4 => 21-4 = 17 Check: The sum = 21+19+17= 57

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Rates

Price

  • $5

Pack prices

  • 5h: $26
  • 10h: $51

online

  • $-1/h

free lessons

The first lesson with Kayode will allow you to get to know each other and discuss your needs for future lessons.

  • 30mins

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